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8x^2-25x-200=0
a = 8; b = -25; c = -200;
Δ = b2-4ac
Δ = -252-4·8·(-200)
Δ = 7025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7025}=\sqrt{25*281}=\sqrt{25}*\sqrt{281}=5\sqrt{281}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5\sqrt{281}}{2*8}=\frac{25-5\sqrt{281}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5\sqrt{281}}{2*8}=\frac{25+5\sqrt{281}}{16} $
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